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15x^2-55x+30=0
a = 15; b = -55; c = +30;
Δ = b2-4ac
Δ = -552-4·15·30
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1225}=35$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-35}{2*15}=\frac{20}{30} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+35}{2*15}=\frac{90}{30} =3 $
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